This lecture covers mainly the singularity works On the effect of advection and vortex stretching and Finite time singularity formation for $C^{1,\alpha}$ solutions to the incompressible Euler equations in $\R^3$ by Elgindi. In the former work Elgindi investigates a blowup mechanism for a simplified 1D model for Euler equation, and then he applies this mechanism to 3D Euler case in the latter one. Conclusively, he constructs a self-similar type blowup vorticity formulated as \begin{equation*} \omega(x,t)=\frac{1}{1-(1+\mu)t}F\br{\frac{|x|^\alpha}{(1-(1+\mu)t)^{1+\lambda}} } \end{equation*}for the 3D incompressible Euler flow with initial data $\omega_0\in C^\alpha$($\alpha$ small enough), where $F$ is a bounded profile. The basic idea is to investigate a fundamental model(which preserves the singularity but is easy enough to solve out the explicit solution), and analyze the singularity under a perturbation by the advection term $u\cdot \nabla \omega$ up to some bounded quantities. Some further discussions and open problems will also be discussed in related topics. 1 Introduction We recall that the incompressible Euler flow is governed by the following equations \begin{equation*} \begin{cases} \partial_t u+u\cdot \nabla u +\nabla p=0,\\ \nabla \cdot u=0, \end{cases} \end{equation*}here $u(x,t)$ is the velocity and $p$ is the pressure. The classic open problem is whether a $C^\infty$-initial data $u_0$ can develop a global smooth formulation. A well-known Beale-Kato-Majda criterion tells us that a classic solution loses its regularity as $t\to T$ iff the vorticity $\omega\coloneqq \nabla \times u$ satisfies \begin{equation*} \lim_{t\to T} \norm{\omega}_{L^1(0,t; L^\infty )}=+\infty. \end{equation*}Consequently, it is natural to consider the vorticity equation\begin{equation*} \partial_t \omega+ u\cdot \nabla \omega=\omega \cdot \nabla u, \end{equation*}and investigate the blowup mechanism of $\omega$. The term $u\cdot \nabla…

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The Hilbert transform is formally defined as \begin{equation*} Hf (x) \coloneqq \text{P.V.} \frac 1{\pi x} * f (x)=\frac 1\pi \int_{-\infty}^{+\infty} \frac{f(y)}{x-y}dx. \end{equation*} Some important facts are listed as follows. The Fourier transform of the kernel \begin{equation*} \Fi\br{\text{P.V.} \frac{1}{\pi x} }=-i \sgn . \end{equation*} We have identities for the Hilbert transform: \begin{equation*} \begin{split} H(Hf)=& -f,\\ H(fg)=& fHg+gHf+H(Hg Hf ),\\ H(fHf)=& \frac12 \br{(Hf)^2-f^2 } . \end{split} \end{equation*} We gives out some classic Hilbert transform: $H (\sin x)= -\cos x, H(\cos x)=\sin x.$ $H \br{\frac{1}{1+x^2}}=\frac{x}{1+x^2}, H\br{\frac{x}{1+x^2} }=\frac{-1}{1+x^2}.$ This lecture is unfinished yet, I will add more contents later. And anyone who offer the detailed calculation of the second one will be appreciated.

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